antisymmetric_mat.md

设$A$为$n$阶方阵,若$a_{ij}=-a_{ji}\quad (i,j=1,2,\cdots,n)$

则称$A$为反称矩阵

显然,

$$a_{ii}=0\quad (i=1,2,\cdots,n)$$

$$A为反称矩阵\iff A^T=-A$$